Universidade Federal do Paraná
Curso de Ciências Biológicas
CE 001 - Bioestatística - 2015/1
Prof. Dr. Walmes Marques Zeviani, Departamento de Estatística - UFPR


Notas, faltas e aprovação

Tabela 1: Notas das avaliações. Tabela organizada pelo número de matrícula dos alunos.
GRR S1 S2 S3 S4 S5 S6 S7 S8 S9 S10 mf F EX MF Aprovação Colocação
20081008 0 44 0 R
20090719 0.00 0.00 0.50 1.00 0.97 0.30 0.35 0.87 0.83 74 12 74 A
20094085 0.64 1.00 1.00 0.95 0.70 0.68 0.73 0.50 82 8 82 A
20094473 0.93 0.00 0.58 0.00 0.80 0.70 0.33 0.87 0.83 74 6 74 A
20095802 1.00 0.00 0.08 12 30 12 R
20100572 0.61 0.67 1.00 0.83 0.33 0.95 0.70 0.60 0.80 0.17 81 2 81 A
20101763 1.00 0.33 0.00 0.42 1.00 0.70 0.78 0.87 0.83 83 14 83 A
20102149 0.41 0.67 0.00 0.33 0.00 0.75 0.70 0.50 0.80 0.17 63 6 32 R
20102195 0.54 0.33 1.00 0.42 0.00 0.95 0.70 0.33 0.80 0.67 76 2 76 A
20102281 0.75 1.00 1.00 0.17 0.00 0.97 0.70 0.62 0.73 0.83 85 2 85 A
20102550 0 44 0 R
20102772 0.93 1.00 0.33 0.90 0.70 0.55 0.80 0.67 81 6 81 A
20103311 0.93 0.00 1.00 0.33 0.00 0.90 0.70 0.70 0.80 0.50 80 4 80 A
20103876 0.93 1.00 1.00 0.33 0.67 0.90 0.65 0.53 0.87 0.67 87 0 87 A
20104973 0.86 0.67 1.00 0.50 0.33 0.95 0.70 0.53 0.00 74 4 74 A
20105088 0 44 0 R
20105205 1.00 1.00 1.00 0.50 0.33 0.97 0.70 0.62 0.00 79 8 79 A
20105219 1.00 1.00 0.50 0.33 0.97 0.70 0.62 0.73 0.33 80 2 80 A
20110638 0.48 0.33 0.50 0.97 0.65 0.53 0.53 0.00 61 14 50 56 A
20110714 0.79 0.00 9 38 9 R
20110822 0.80 1.00 0.33 0.00 0.70 0.70 0.55 0.80 0.20 71 12 71 A
20111651 0.33 1.00 0.17 0.00 0.80 0.50 0.45 0.67 0.00 60 6 50 55 A
20113106 0.88 0.17 1.00 0.00 0.50 0.20 33 10 33 R
20113322 0.68 1.00 1.00 0.83 1.00 0.90 0.70 0.60 0.67 85 6 85 A
20113436 1.00 1.00 1.00 0.83 0.33 1.00 0.75 0.65 0.73 0.83 91 2 91 A Luana W Almeida (4º)
20114607 0.80 0.67 0.00 0.00 0.95 0.70 0.70 0.80 0.33 74 8 74 A
20114874 0.27 0.33 1.00 0.67 0.00 1.00 0.90 0.75 0.67 78 4 78 A
20119954 0.93 0.67 1.00 0.42 0.00 0.90 0.70 0.55 1.20 0.17 89 10 89 A
20120049 0.68 1.00 0.92 1.00 0.80 0.85 0.57 0.80 0.67 85 8 85 A
20123768 1.00 1.00 0.42 0.00 0.97 0.80 0.72 0.80 0.83 88 2 88 A
20123769 0.93 1.00 1.00 0.83 1.00 0.00 0.57 0.67 0.17 85 6 85 A
20123770 0.86 0.67 1.00 0.67 0.00 0.97 0.70 0.85 0.60 0.00 81 10 81 A
20127148 0.93 0.33 0.00 0.08 0.00 0.75 0.50 0.70 0.87 0.83 73 6 73 A
20127165 1.00 1.00 0.25 0.00 0.97 0.80 0.72 0.67 0.83 85 4 85 A
20127179 1.00 0.00 0.08 0.00 0.90 0.70 0.60 0.67 0.83 71 10 71 A
20127305 0.48 0.67 1.00 0.50 0.33 0.97 0.70 0.55 0.87 1.00 84 6 84 A
20127306 0.59 0.33 1.00 0.83 0.17 0.97 0.70 0.85 0.87 1.00 90 2 90 A
20127311 0.75 1.00 1.00 0.92 1.00 0.97 0.80 0.85 0.87 1.00 95 0 95 A Camila P Perico (2º)
20127312 0.39 1.00 0.00 0.00 0.00 0.90 0.70 0.33 0.80 1.00 76 10 76 A
20127315 0.68 0.67 1.00 0.50 0.33 1.00 0.70 0.35 0.87 0.00 81 8 81 A
20127317 0.88 0.67 1.00 1.00 1.00 0.97 0.80 0.85 0.80 0.83 92 2 92 A Pedro A P Franzoi (3º)
20127322 0.93 0.67 1.00 0.58 1.00 0.85 0.80 0.62 0.47 0.17 81 0 81 A
20127323 0.55 0.50 1.00 0.00 0.97 0.70 0.13 0.00 55 12 50 52 A
20127328 1.00 1.00 1.00 0.75 0.00 1.00 0.70 0.70 0.80 89 2 89 A
20127329 1.00 1.00 1.00 0.83 0.67 0.97 0.95 0.68 0.87 1.00 96 0 96 A Kathleen L Kolb (1º)
20127333 0.39 1.00 0.50 0.67 0.00 1.00 0.70 0.75 0.73 0.83 82 6 82 A
20127343 1.00 1.00 0.00 0.33 0.00 0.90 0.95 0.53 0.73 0.67 82 6 82 A
20127345 1.00 1.00 1.00 0.83 1.00 1.00 0.70 0.70 0.73 1.00 95 0 95 A Thays V Prestes (2º)
20127347 1.00 0.00 0.17 0.00 1.00 0.80 0.47 0.73 0.67 73 8 73 A
20127354 0.48 1.00 1.00 0.25 0.00 1.00 0.72 0.80 0.50 81 2 81 A
20127355 1.00 0.33 1.00 0.78 1.00 0.75 0.72 0.60 0.83 85 6 85 A
20142143 0.71 0.17 0.00 10 28 10 R
20143033 0.73 0.17 1.00 21 34 21 R
20143890 0.71 0.17 0.00 10 30 10 R

Cálculo da média final

A média final é calculada da seguinte forma. Vamos considerar a nota do(a) aluno(a) com a maior média final, Kathleen L Kolb.

  1. As suas notas e os respectivos pesos estão na tabela acima.
  2. Cada nota é repetida o número de vezes do seu peso e sem seguida elas são ordenadas da maior para a menor. Sendo assim as notas são 1.00, 1.00, 1.00, 1.00, 0.97, 0.97, 0.95, 0.87, 0.87, 0.83, 0.68, 0.67;
  3. Toma-se a parte inteira do produto entre a soma dos pesos e 0.75, assim, tem-se \(m = \left\lfloor 0.75 n \right\rfloor = \left\lfloor 0.75\cdot 12 \right\rfloor = 9\);
  4. Faz-se a média das \(m\) primeiras notas em ordem decrescente, \(\dfrac{1.00+1.00+1.00+1.00+0.97+0.97+0.95+0.87+0.87}{9} = 0.96\);
  5. Multiplica-se por 100 e arredonda-se para o inteiro mais próximo.